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5n^2-7n-258=0
a = 5; b = -7; c = -258;
Δ = b2-4ac
Δ = -72-4·5·(-258)
Δ = 5209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{5209}}{2*5}=\frac{7-\sqrt{5209}}{10} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{5209}}{2*5}=\frac{7+\sqrt{5209}}{10} $
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